FBISE Class 9 Physics ke chapter ke yeh do important numericals solve kar dein: ek 5000 g ko prefixes mein express karna aur doosra hair growth rate 1 mm per day ko nm s^-1 mein find karna?

Yeh sawal FBISE Class 9 Physics se related hai, jo ke mere Chemistry domain se thora bahar hai. Lekin main aapki madad ke liye is chapter ke do bohot important numericals simple tareeqe se solve kar deti hoon: ### Numerical 1: Express 5000 g using prefixes. * **Given Data:** Mass = $5000\text{ g}$ * **To Find:** Value in terms of prefix. * **Solution:** Hum jante hain ke $1000 = 10^3 = \text{kilo (k)}$. $5000\text{ g} = 5 \times 10^3\text{ g}$ Kyunki $10^3\text{ g} = 1\text{ kg}$, hum likh sakte hain: $\text{Mass} = 5\text{ kg}$ * **Answer:** $5\text{ kg}$ --- ### Numerical 2: Your hair grows at the rate of 1 mm per day. Find their growth rate in $\text{nm s}^{-1}$. * **Given Data:** * Growth rate = $1\text{ mm/day}$ * Distance ($s$) = $1\text{ mm} = 1 \times 10^{-3}\text{ m}$ * Time ($t$) = $1\text{ day} = 24 \times 60 \times 60\text{ seconds} = 86400\text{ s}$ * **To Find:** Growth rate in nanometers per second ($\text{nm s}^{-1}$) * **Solution:** $\text{Growth Rate} = \frac{\text{Distance}}{\text{Time}}$ $\text{Growth Rate} = \frac{1 \times 10^{-3}\text{ m}}{86400\text{ s}}$ $\text{Growth Rate} = 1.157 \times 10^{-8}\text{ m s}^{-1}$ Ab isay nanometers ($10^{-9}\text{ m}$) mein convert karne ke liye hum decimal point ko ek digit right side move karenge: $\text{Growth Rate} = 11.57 \times 10^{-9}\text{ m s}^{-1}$ Kyunki $10^{-9} = \text{nano (n)}$, toh: $\text{Growth Rate} = 11.57\text{ nm s}^{-1}$ * **Answer:** $11.57\text{ nm s}^{-1}$ Kya yeh dono numericals ke steps clear hain? Agar Chemistry mein koi topic samajhna ho, toh zaroor batayein! [[SUGGEST_GROUP:Physics]]