Agar 1929 mein Jaranwala mein zameen ka rate PKR 20 per marla assume kiya jaye, toh 10 Thompson submachine guns ki qeemat se 1929 aur aaj ke daur mein kitni zameen khareedi ja sakti hai?

Answered by Prof. Zeeshan

Theek hai, agar hum 1929 ke liye Jaranwala mein **PKR 20 per marla** ka rate assume karte hain, toh calculations dekhte hain: **1929 ka Scenario (Hypothetical, with your assumed rate):** * Humne pehle dekha ke 1929 mein 10 Thompson submachine guns ki qeemat lagbhag **$2,000** thi. * Ab, us waqt ke $2,000 ko British Indian Rupees mein convert karna hoga. 1929 mein, 1 US Dollar ki value lagbhag **3.5 British Indian Rupees** thi (yeh figure bhi historical data se liya gaya hai aur thoda vary kar sakta hai). * Toh, $2,000 = 2,000 x 3.5 = **7,000 British Indian Rupees**. * Agar Jaranwala mein zameen ka rate **20 Rupees per marla** tha: * Kitne marle zameen = Total Rupees / Rate per Marla * Marle = 7,000 / 20 = **350 marle** **Conclusion for 1929 (with your assumed rate):** Agar 1929 mein Thompson submachine gun ki qeemat $200 per gun thi aur Jaranwala mein zameen ka rate 20 Rupees per marla tha, toh **10 Thompsons ($2,000 ya 7,000 British Indian Rupees) se aap Jaranwala mein 350 marle zameen khareed sakte the.** **Aaj ka Scenario (2026):** * Yeh calculation pehle jaisa hi rahega. * 10 fully automatic Thompsons ki qeemat (approx. $20,000 x 10 = $200,000) = **PKR 55,409,960**. * Jaranwala mein average property rate **PKR 500,000 per marla** hai. * Toh PKR 55,409,960 mein kitne marle zameen aayegi: * Marle = 55,409,960 / 500,000 = **110.82 marle** **Final Comparison:** * **1929 mein:** 10 Thompsons = **350 marle** zameen (Jaranwala, assumed rate 20 Rs/marla) * **Aaj (2026) mein:** 10 Thompsons = **110.82 marle** zameen (Jaranwala, assumed rate 500k Rs/marla) Is calculation ke mutabiq, meme ka premise (ke Thompson ki purchasing power stable rahi hai) Jaranwala ke context mein sahi nahi lagta, kyunki 1929 mein aap zyada zameen khareed sakte the. Lekin, yeh sab assumptions par based hai.